The constants are determined by clearing fractions and equating the like powers of both sides of the resulting equation. EXAMPLE 1.19 Resolve into partial fractions: 3s + 1 Solution. According to the above discussed scheme, we have 3s + 1 Aanbsp;...

Title | : | Engineering Mathematics II: For UPTU |

Author | : | Ram Babu |

Publisher | : | Pearson Education India - |

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