Now take 2.48 x 10aquot;3 k[o.0080Mln a = a a and dividing leaves, 4 = 6.2 x 10aquot; k[ o.0040M]n the log of both sides of the ... Plug it into any of the [rate expression rate = k[HBr]2 and solve k: 6.2 x 10aquot;4 mol/L s - k[0.0040]2 ; k = 39 L/mol s c. rate = k[HBr]2 - (39 ... So, m must be 0 since anything to the zero power is equal to 1 .

Title | : | Essential Chemistry Problems |

Author | : | David Margolese, David W. Oxtoby |

Publisher | : | Brooks/Cole Publishing Company - 2004-04-01 |

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